문제


정답
SELECT a.REST_ID, a.REST_NAME, a.FOOD_TYPE, a.FAVORITES, a.ADDRESS, ROUND(AVG(b.REVIEW_SCORE), 2) AS SCORE
FROM REST_INFO AS a
JOIN REST_REVIEW AS b
ON a.REST_ID = b.REST_ID
WHERE a.ADDRESS LIKE '서울%'
GROUP BY a.REST_ID, a.REST_NAME, a.FOOD_TYPE, a.FAVORITES, a.ADDRESS
ORDER BY SCORE DESC, a.FAVORITES DESC;
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